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64 lines
1.8 KiB
Python
64 lines
1.8 KiB
Python
#!/usr/bin/env python3
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# Copyright 2021 Xiaomi Corp. (authors: Fangjun Kuang)
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#
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# See ../../LICENSE for clarification regarding multiple authors
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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"""
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You can run this file in one of the two ways:
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(1) cd icefall; pytest test/test_decode.py
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(2) cd icefall; ./test/test_decode.py
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"""
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import k2
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from icefall.decode import Nbest
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def test_nbest_from_lattice():
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s = """
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0 1 1 10 0.1
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0 1 5 10 0.11
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0 1 2 20 0.2
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1 2 3 30 0.3
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1 2 4 40 0.4
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2 3 -1 -1 0.5
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3
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"""
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lattice = k2.Fsa.from_str(s, acceptor=False)
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lattice = k2.Fsa.from_fsas([lattice, lattice])
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nbest = Nbest.from_lattice(
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lattice=lattice,
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num_paths=10,
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use_double_scores=True,
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nbest_scale=0.5,
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)
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# each lattice has only 4 distinct paths that have different word sequences:
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# 10->30
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# 10->40
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# 20->30
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# 20->40
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#
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# So there should be only 4 paths for each lattice in the Nbest object
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assert nbest.fsa.shape[0] == 4 * 2
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assert nbest.shape.row_splits(1).tolist() == [0, 4, 8]
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nbest2 = nbest.intersect(lattice)
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tot_scores = nbest2.tot_scores()
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argmax = tot_scores.argmax()
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best_path = k2.index_fsa(nbest2.fsa, argmax)
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print(best_path[0])
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